Ray Lee

So that was too easy?

Most people seemed to find that first Patrick Jourdain problem preented too little challenge.  Okay, try this one instead.  West is in 5on a spade lead.



West East
A 65432
2 A6543
QJ10932 K
QJ1098 A2


Neil KimelmanNovember 24th, 2008 at 6:55 pm

Ok, I’ll bite. Looks like I can’t make it against most 4-2 diamond breaks unless the K of clubs is onside. Then I still might go down on a 5-1 diamond break. Win the spade hook the club. If it lives, cash the club ace, ruff a heart ruff a club and try to ruff a major low. If the club loses, I need diamonds 3-3 and will pitch my club A when I pull trumps.

ColinNovember 25th, 2008 at 12:22 am

pretty sure I got this one – don’t want to ruin it for other readers – but I would say that you should be able to make it on 4-2 diamond breaks (almost all) and that the theme is too similar 🙂

Luise LeeNovember 25th, 2008 at 5:19 am

I figured it out! YAY 🙂

I am so smart… S… M… R… T… I mean, S M A R T!

Neil KimelmanNovember 25th, 2008 at 9:20 pm

I can count to 13, but apparently not to 11 :-). Cross to the diamond king, and play the 2C to my hand, and eventually discard the A of clubs. The defence may still be able to negotiate a club ruff on this line, but don’t see a 100% line.

Luise LeeNovember 25th, 2008 at 11:46 pm

I didn’t see a 100% line either, but I figured if I can make it when any suit breaks as bad as 4-2 or 5-2, that’s probably good enough. If they have a stiff-anything, I’m probably going down.

Luise LeeNovember 26th, 2008 at 12:36 am

Hmm… I’m not so sure on my solution anymore.

Ray LeeNovember 29th, 2008 at 9:24 pm

No 100% line — this is real life! You all have it figured out though.

Leave a comment

Your comment